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UploadFile

JS Py

Hello World

Uploads a file to a server.

app.UploadFile( url, file, name, callback? )

Example - Upload File

function OnStart()
{
    var name = app.GetAppName() + ".js";
    var file = app.GetAppPath() + "/" + name;
    app.UploadFile( "https://yourwebsite.com/upload", file, name, OnUpload );
}

function OnUpload( error, file, result )
{
    if(error) app.Alert( "Upload Failed!" )
    else app.ShowPopup( "Response:\n" + result, "Upload Successful!" );
}

from native import app

def OnStart():
    global file
    name = app.GetAppName() + ".js"
    file = app.GetAppPath() + "/" + name
    app.UploadFile("https://yourwebsite.com/upload", file, name, OnUpload)

def OnUpload(error, file, result):
    if error:
        app.Alert("Upload Failed!")
    else:
        app.ShowPopup("Response:\n" + result, "Upload Successful!")

Copy All Run

String

String: path to file ( “/absolute/...” or “relative/...” )

String: url path

function()